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compute f'(a) for f(x)=4-x^2, a=-1
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f'(x) = -2x f'(a) = -2(-1) f'(a) = 2 Where a = -1
agreene has a good answer, which means this is also a "good answer" hint hint
how do you get f'(x) = -2x ?
It's a shortcut for derivatives
f'(x) is the derivative of f(x). This particular derivative can be done using the power rule. whereby you drop the power off the variables multiply them by their constants and for variables with powers of 1 they go away. constants go to 0. F(x) = 4 - x^2 4 is constant and goes to 0 -x^2 has power two, coeff 1. so you can drop power 2(1) =1 F'(x) = -2x
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2(1) = 2 ... im dumb.
If f(x) - x^5, the f'(x)= -5x^4.
oh i get it.....somewhat. thanks a lot
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