Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (anonymous):

Suppose P is invertible and PBP^-1 . Solve for B in terms of A

OpenStudy (anonymous):

I'm supposing you meant A=PBP^-1. Matrix multiplication is NOT commutative. But you can multiply both sides of an equation by a matrix as long as you keep the matrix on the same side on both sides. Wait what? How about an illustration: Let A, B, and X be matrices with A=B. Then AX = BX and XA = XB, but you can't say AX = XB or XA = BX. Having said that, PP^-1 = P^-1P = I, and AI = IA = A, so there it kinda looks commutative. So multiply both sides of the equation by P and P^-1 in the right places, and you'll solve for B.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!