Question

Simplify the expression. Write the result using positive exponents. 3x^3y^3/-8x^2y^9 teach me please?

Answer 1

x^3 divided by x^2, you get x.
y^3 divided by y^9, you get y^-6.

since you need to get positive exponents. y^-6 moves to the bottom and becomes y^6.

final answer: 3x/8(y^6)

Answer 2

i forgot the negative sign. sorry!

-3x/8(y^6)

Answer 3

ah..ok

Answer 4

\[\large{\frac{3x^3y^3}{8x^2y^9}}\]
rules of exponents:
\[\large{\frac{x^m}{x^n}}= x^{m-n}\]\[\large{x^{-m}=\frac{1}{x^m}}\]

Answer 5

first factor out the constants
\[\large{\frac{3}{8}(\frac{x^3y^3}{x^2y^9}})\]

Answer 6

now look at the x first
since its
\[\large{\frac{x^3}{x^2} so =x^{3-2}}=x\]

Answer 7

then look at the y
\[\large{\frac{y^3}{y^9}=y^{3-9} = y^{-6}}\]

Answer 8

so now you have
\[\large{\frac{3}{8}(xy^{-6}})\]

Answer 9

and u know that
\[\large{x^{-m}=\frac{1}{x^m}} so .. y^{-6}=\frac{1}{y^{6}}\]

Answer 10

there fore the final answer is
\[\large{\frac{3x}{8y^6}}\]

Answer 11

and just put that negative that i forgot :)

Answer 12

okay thanks