2(x+1)^2 =2(x+1)(x+1)???
you realize that we have (x+1)^2 on both sides right?
thats not my answer, i just want to know if 2(x+1)^2 can be written as2(x+1)(x+1)
then perhaps you should specify that in your question. And yes it can be written that way
could you tell me the answer?
what answer? the two sides are equal
so is the who term raised to the 2nd power, or just the (x-1)??
no only the (x+1) term is
so how can they both be equal????
(x+1)^2=x^2+2x+1 (x+1)(x+1)=x^2+2x+1
it is 2(x+1)^2
what i wrote above tells you that both sides of the equation are equal you can write it either way
I am confused, what I did is; 2(x+1)^2 =2(x+1)(x+1) =2x+2(x+1)
let me write it this way: 2(x+1)^2=2(x^2+2x+1). 2(x+1)(x+1)=2(x^2+2x+1) We have to take care of the parentheses first.
did you distribute the 2 through both parentheses?
you can if you want to
but is that what you are suppose to do?
what did you do???
depends on what the directions say, but if i were you i wuld distribute the 2 into the parentheses
thanks
I got 2x^2+4x+2????
nice job, that is the correct way to distribute the 2
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