Question

solve s^2+14s+48=0

Answer 1

Quadratic formula, do you know it?

Answer 2

Factors nicely as
(s+6)(s+8)=0
s=-6
s=-8

Answer 3

no idont know it

Answer 4

\[(-b \pm \sqrt{b ^{2}-4ac}\div2a\]

Answer 5

I suck at equation editor.

Answer 6

\[(-b \pm \sqrt{b ^{2-4ac)}}\div2a\]

Answer 7

For this problem
a=1
b=14
c=48
just plug them into the quadratic formula as jmtrapasso suggested, however for the given equation factoring is easier.

Answer 8

The quadratic formula works for equations in the form of ax^2 +bx + c = 0 which is what you have. Radar told you what each stand letter stands for so try to plug it in yourself. But yea for this problem factoring is perfect, was just trying to teach you a new way that you sometimes have to do and it's sometimes quicker.

Answer 9

Here is the formula if you want to try it

\[-b \pm \sqrt{b ^{2}-4ac}\over2a\]This will give you the roots of the equation.

Answer 10

If the equation is prime, then factoring is not the way to go.

Answer 11

s^(2)+14s+48=0

In this problem 8*6=48 and 8+6=14, so insert 8 as the right hand term of one factor and 6 as the right-hand term of the other factor.
(s+8)(s+6)=0

Set each of the factors of the left-hand side of the equation equal to 0.
s+8=0_s+6=0

Since 8 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 8 from both sides.
s=-8_s+6=0

Set each of the factors of the left-hand side of the equation equal to 0.
s=-8_s+6=0

Since 6 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 6 from both sides.
s=-8_s=-6

The complete solution is the set of the individual solutions.
s=-8,-6