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Mathematics 7 Online
OpenStudy (anonymous):

In a quadratic equation, and the discriminant is zero, is the solution zero as well? Explain

OpenStudy (saifoo.khan):

No

OpenStudy (saifoo.khan):

there will be just one solution

OpenStudy (saifoo.khan):

The curve will cute the x-axis single time,

OpenStudy (anonymous):

cute?

OpenStudy (saifoo.khan):

Cute? o_O

OpenStudy (chaise):

Saifoo is right (: When: b^2 -4ac = 0; one REAL solution b^2 -4ac > 0; two REAL solutions b^2 -4ac < 0; two IMAGINARY solutions. Not sure if there is any other combinations.

OpenStudy (anonymous):

the solution is the double root \[x=\frac{-b}{2a} \]for\[ax^2-bx+c=0\]

OpenStudy (anonymous):

Given a quadratic equation of the form \[ax^{2} + bx + c = 0\]the quadratic formula tells us that the solutions to the equation are at \[x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\]The term\[b^{2}-4ac\]is called the "discriminant" because it can be used to "discriminate" among the cases chaise mentioned above. Now, if the discriminant is 0, the whole fraction doesn't go to 0, just the square root part. That leaves use with \[x=\frac{-b}{2a}\]If b and a are nonzero then x will be nonzero.

OpenStudy (anonymous):

very nice

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