A 0.224 kg billiard ball moving at a speed of 12.0 m/s strikes the side of the table at 30 degree angle with the horizontal. the ball rebounds at the same speed and angle. What is the change in momentum of the ball?

Question

anonymous · Answer

2*0.224*12

anonymous · Answer

I think it's 2.688 kg m/s.

anonymous · Answer

how did you come-up with that answer?, if I may ask.

anonymous · Answer

$$m v_2- m v_1$$

anonymous · Answer

$$m(v_1 -(-v_1))$$

$$m(v_1 +v_1)$$

$$m(2v_1)$$

anonymous · Answer

What have you tried, to come up with the answer?

anonymous · Answer

my answer is -5.376 kgm/s using deltap=pf-pi

anonymous · Answer

I think you're referring to a picture that we can't see.  Can you draw the picture?

anonymous · Answer

|dw:1318046498636:dw| that is how i interpret it.