Question

what is the length of the major axis in this ellipse?
(x-4)^2/16+(y+3)^2/25=1
a.10
b.50
c.8
d. 32
e. none of the above

Answer 1

verify?

Answer 2

\[\frac{(x-4)^2}{16}+ \frac{(y+3)^2}{25}=1 \]The square root of 25 is the semi-major axis. 2*5 = 10 is the length of the major axis.

Refer to the attachment

Answer 3

Thank you for the medal.

Answer 4

no problem, thanks for the help