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Mathematics 22 Online
OpenStudy (anonymous):

a ue of indices

OpenStudy (anonymous):

1/[1+x+(y^-1)]+1/[1+y+(z^-1)]+1/[1+z+(x^-1)]

OpenStudy (anonymous):

help me step by step plz

OpenStudy (anonymous):

can you pls rewrite the question, i can't see it properly.

jhonyy9 (jhonyy9):

1 1 1 -------- + --------- + ---------- = 1+x+1/y 1+y+1/z 1+z+1/x 1 1 1 ---------- + ---------- + ----------- = (y+xy+1) (z+zy+1) (x+xz+1) --------- --------- --------- y z x y z x = --------- + ---------- + --------- (y+xy+1) (z+zy+1) (x+xz+1)

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