What is the solution set of |x + 3| – 2 = –5?
You see that |x+3| = -3 Do you agree so far?
I have no idea what to do, honestly.
Ok. So, I added 2 to each side |x+3| - 2 + 2 = -5 + 2 Hence |x+3| + 0 = -3 |x+3| = -3 Yes?
Oh. okay. I see now...
either x+3 or -x-3 would be used to replace the absolute value sign so.. x + 3 - 2 = 5 or -x - 3 - 2 = 5 solve
Good. Now we have a problem.
@gspade: totally wrong, sorry. Is there ANY number y such that |y| = -3 ?
Because |3| = 3 and |-3| = 3. So is there any number y such that |y| = -3 ?
agree with JamesJ
So to recap. So far we shown the original problem is equivalent to the problem of find x such |x+3| = -3 Now the question I am raising is this: can that equation even have any solutions in theory?
That is, are there ANY numbers y that have the property that | y | = -3 ?
Ok. You've buggered off. But think about what I'm asking. Good luck.
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