Question

answer in radical form
16^(1/3)y^3

Answer 1

\[y^3\sqrt[3]{16}\]

Answer 2

the y^3 is not under a radical because the denominator of its exponent is a 1; the exponent of 1/3 means cube root; the factors to 8*2 where 8 is a perfect cube
\[16^{1/3}y^3=y^3\sqrt[3]{8*2}=2y^3\sqrt[3]{2}\]

Answer 3

the original question was