Question

see below

Answer 1

a+5??

Answer 2

a + 5 + \[\sqrt{10a}\]

Answer 3

almost, you need absolute value bars around the expression unless you are told thata is >=5\[\sqrt{(a+5)^2}=\left| a+5 \right|\]

Answer 4

jmt, I think you misread the a

Answer 5

Since x can be any real number\[\sqrt{x^2}=\left| x \right|\]consider these examples\[\sqrt{2^2}=2\]no problem in this one the root is non=negative as it must be, but\[\sqrt{(-2)^2}=-2\]bu the principle square root can't be negative so we must have the absolute value, ie, the corrected version is\[\sqrt{(-2)^2}=\left| -2 \right|=2\]

Answer 6

\[\sqrt{a^2 +10a +25}\]

Answer 7

(a+5)

Answer 8

because there is like exponent first 2 and sqrt is like exponent 1/2 so when there is exponent on exponent we need multiply those exponentes and 2*1/2 is 1 thie resulted that we will get like result at finaly (a+5)