Mathematics
21 Online
OpenStudy (anonymous):
the sides of a square are lengthened by 6cm, the area then becomes 196cm^2. what is the area of the original square?
172cm^2?
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OpenStudy (anonymous):
Solve (x+6)^2=196
OpenStudy (anonymous):
x=8
OpenStudy (anonymous):
x^2 + 12x + 36 = 196
OpenStudy (anonymous):
Apply square root to both sides first is easier ag....go
OpenStudy (anonymous):
pixie! you been here all evening?
dang. as mandolino said, solve
\[(x+6)^2=198\]
\[x+6=\sqrt{196}=14\]
\[x=14-6=8\]
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OpenStudy (anonymous):
so 32 is the area of the original square?
OpenStudy (anonymous):
yes!
OpenStudy (anonymous):
yeah, been here almost all night lol, trying to finish my final
OpenStudy (anonymous):
on line class?
OpenStudy (anonymous):
oh wait!!
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OpenStudy (anonymous):
\[8^2=64\] not 32
OpenStudy (anonymous):
8*8=64
OpenStudy (anonymous):
so original square had area 64, not 32
OpenStudy (anonymous):
ok, so what would the length of one side be then? 8?
OpenStudy (anonymous):
online class yeah 17 more questions to go
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OpenStudy (anonymous):
length of one side is 8, area is 64
OpenStudy (anonymous):
dang how many questions in this final, and how much time are you given?
OpenStudy (anonymous):
not due til tomorrow night, but still have another final to do, 2000+ word paper lol