Question

hookies law. the distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. if the distance is 50 cm when the weight is 7kg what is the distance when the weight is 5kg.

Answer 1

F = -kd

Answer 2

or W = -kd

Answer 3

or W = kd

Answer 4

F=kx
mg=kx--1
m1=7kg
x1=0.5m

m1g=kx1
k=m1g/x1
k=137.2
m2g=kx2
5kg*9.8m/s^2=137.2kg/s^2*x2
x2=0.357142 m
x2=35.7

Answer 5

35.7cm

Answer 6

And for the record, it's not Hookies Law or alas even Hookers Law, but

Hooke's Law.