Question

7(3x+2)^2(1-x)^2+(3x+2)(1-x)^3=

Answer 1

are you supposed to multiply out or factor?

Answer 2

factor compleatly and simplify

Answer 3

completely

Answer 4

ok then ignore my answer to your last problem. i thought it meant multiply

Answer 5

ok

Answer 6

ok

Answer 7

this one factors as
\[5 (x-1)^2 (3 x+2) (4 x+3)\]

Answer 8

the 1st one

Answer 9

each term has a common factor of
\[(3x+2)(1-x)^2\]

Answer 10

you need an answer to your first question as well?

Answer 11

yes

Answer 12

\[(4 x-3) (60 x-23)\]

Answer 13

that is the answer to the one i multiplied out earlier. there it is in factored form

Answer 14

i have to work the whole thing out and i really am not good at this

Answer 15

ok which one would you like to do?

Answer 16

the one that started with 5 thanks

Answer 17

let me go find it hold on

Answer 18

\[5(3-4x)^2-8(3-4x)(5x-1)=\]

Answer 19

ok this one is easier than the second one. each term has a common factor. it is
\[3-4x\]

Answer 20

ok

Answer 21

so before we do this, lets imagine we had
\[5a^2-8ab\] and we wanted to factor

Answer 22

i see a common factor of "a" in each term so i "factor it out" and write
\[a(5a-8b)\]

Answer 23

k

Answer 24

we are going to do exactly the same thing, but with
\[a=3-4x \text{ and } b=5x-1\]

Answer 25

so we write
\[(3-4x)(5(3-4x)-8(5x-1))\]

Answer 26

so we write
\[(3-4x)(5(3-4x)-8(5x-1))\]

Answer 27

i am guessing that is the confusing step, so let me know if it is not clear

Answer 28

but the line above looks just like
\[a(5a-8b)\] as i wrote before, but with the replacements for a and for b

Answer 29

yes

Answer 30

yes as in "yes it is confusing"? or yes as in "ok i get it more or less"

Answer 31

where is the 2nd part of 3-4x

Answer 32

confusing

Answer 33

ok lets go slow

Answer 34

we start with
\[5(3-4x)^2-8(3-4x)(5x-1)=\]

Answer 35

each term has a common factor. it is
\[(3x-4)\]
that much ok?

Answer 36

y

Answer 37

ok so what is it being multiplied by in the second term? it is being multiplied by
\[-8(5x-1)\] because you see
\[-8(3x-4)(5x-1)\]

Answer 38

and in the first term you have
\[5(3x-4)=5(3x-4)(3x-4)\]

Answer 39

so in the first term it is being multiplied by
\[5(3x-4)\]