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Mathematics
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lim ((1/(x+h))-(1/x))/h h->0
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guess you are trying to find the derivative of \[f(x)=\frac{1}{x}\] right?
ya
i know the answer is 1/x^2 but we need to use that formula and solve it
actually it is \[-\frac{1}{x^2}\]
you just have to do the algebra \[\frac{1}{x+h}-\frac{1}{x}=\frac{x-(x+h)}{x(x+h)}=\frac{-h}{x(x+h)}\]
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now divide all this mess by h, so the h cancels in the numerator to give you \[\frac{-1}{x(x+h)}\] and finally take the limit as h goes to zero and you are done
oh wow that was easy thank you
yw
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