Question

solve for x:
log(8x + 9) = 2 + log(3x − 4)

Answer 1

log(8x)*log(9) = 2+log(3x)/log(4)
x=2.72152

Answer 2

\[\log \left( \frac{8x + 9}{3x - 4} \right) = 2\]
\[\frac{8x + 9}{3x -4} = 100\]
\[8x + 9 = 300x - 400\]
\[292x = 409\]
\[x = 409/292 = 1 \frac{117}{292}\]

Answer 3

kira, how does 2 = 100?

Answer 4

When you drop the log, it becomes 10^2 = 100...

Answer 5

he assumed that log had base 10

Answer 6

is that the case?

Answer 7

thanks so much! makes sense finally lol

Answer 8

log(8x+9) = log10^2 + log(3x-4)
=> log(8x+9) = log (3x-4)(100)
=> 8x+9 = 300x - 400
=> 292 x = 409
=> x = 409/292

Answer 9

log(8x+9) = log10^2 + log(3x-4)
=> log(8x+9) = log (3x-4)(100)
=> 8x+9 = 300x - 400
=> 292 x = 409
=> x = 409/292

Answer 10

log(8x+9) = log10^2 + log(3x-4)
=> log(8x+9) = log (3x-4)(100)
=> 8x+9 = 300x - 400
=> 292 x = 409
=> x = 409/292