solve for x:
log(8x + 9) = 2 + log(3x − 4)

Question

anonymous · Answer

log(8x)*log(9) = 2+log(3x)/log(4)
x=2.72152

kira_yamato · Answer

$$\log \left( \frac{8x + 9}{3x - 4} \right) = 2$$
$$\frac{8x + 9}{3x -4} = 100$$
$$8x + 9 = 300x - 400$$
$$292x = 409$$
$$x = 409/292 = 1 \frac{117}{292}$$

anonymous · Answer

kira, how does 2 = 100?

kira_yamato · Answer

When you drop the log, it becomes 10^2 = 100...

anonymous · Answer

he assumed that log had base 10

anonymous · Answer

is that the case?

anonymous · Answer

thanks so much! makes sense finally lol

vishweshshrimali5 · Answer

log(8x+9) = log10^2 + log(3x-4)
=> log(8x+9) = log (3x-4)(100)
=> 8x+9 = 300x - 400
=> 292 x = 409
=> x = 409/292

vishweshshrimali5 · Answer

log(8x+9) = log10^2 + log(3x-4)
=> log(8x+9) = log (3x-4)(100)
=> 8x+9 = 300x - 400
=> 292 x = 409
=> x = 409/292

vishweshshrimali5 · Answer

log(8x+9) = log10^2 + log(3x-4)
=> log(8x+9) = log (3x-4)(100)
=> 8x+9 = 300x - 400
=> 292 x = 409
=> x = 409/292