Can somebody tell me how to solve this using bernoulli's equation

[y^2(x+1)+y]dx+(2xy+1)dy=0

Question

Can somebody tell me how to solve this using bernoulli's equation

[y^2(x+1)+y]dx+(2xy+1)dy=0

jamesj · Answer

So dy/dx = - [y^2(x+1)+y]/(2xy+1)

Can you just confirm you've written this down correctly (and I have as well!)

anonymous · Answer

correct!

jamesj · Answer

In general, a Bernoulli equation is one of the form
y' + p(x)y = q(x)y^n

It's not clear to me right now how we're going to change variables or otherwise manipulate your  equation to get it in this form.  But let me play with it a little more

anonymous · Answer

thnaks , i've tried a million ways but it's turned into a nightmare

jamesj · Answer

It looks a bit nightmarish right now.

anonymous · Answer

is there another ways of solving it?
maybe using a different method?

jamesj · Answer

I'm beginning to try and reverse engineer a method from this solution, assuming it is a solution: http://www.wolframalpha.com/input/?i=%5By^2%28x%2B1%29%2By%5Ddx%2B%282xy%2B1%29dy%3D0 But it really is nasty and I'm not going to have any more time this morning. Just triple check this is the problem they gave you, as it's very nasty for an intro ODE course, which I assume you're taking.