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Cauchy Integral Question...
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Now you're just keeping us in suspense.
Congratulations on achieving "Master" James, you sure deserve it.
thanks
Find\[\int\limits_c \frac{1}{z-1}dz\] where C is any circle centred at z=1 with the usual counterclockwise orientation:\[\gamma(t)=1+Ae^{2\pi i t} , 0\le t \le1\]. Sorry it took so long to post the question. I forgot all the shortcuts on how to write the equations...
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This is very straightforward, as 1/(z-1) = 1/A . exp(-2pi.i.t) and dz = 2 A pi.i.exp(2pi.i.t)
so what does your integral simplify to?
dz = 2 A pi.i.exp(2pi.i.t) dt
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