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COuld someone help me on this question, Find the derivative: f(x) = 3x^5-5x^3+4
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f'(x) = 15x^4 -15x
sorry, second term is -15x^2
Any chance you could tell me the steps? thanks
f(x)=ax^n f'(x)=nax^(n-1) so for f(x)=3x^5-5x^3+4(x^0) f'(x)=5(3x^4)-3(5x^2)+0=15x^4-15x^2
thanks
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