Question

Given:
Volume of vinegar = 5mL
Concentration of NaOH = 0.1188 M
Average volume of NaOH from titration = 26.50mL

How would I go about with finding:
- mol NaOH req. to reach equivalence pt?
- mol acetic acid 5.00mL of vinegar
- mass of acetic acid in 5.00mL sample of vinegar
- volume of acetic acid in 5.00mL sample of vinegar
- % by vol. of acetic acid in vinegar

Answer 1

To find the mol NaOH, multiply the volume of NaOH (adjusted to L) by the molarity, which gives you the total molar amount of NaOH. Because youre using titration, the moles of NaOH must equal the moles of the analyte (ie vinegar) so your mole value for NaOH will equal the mole value for acetic acid. After that, you have the volume of vinegar, which can be used to calculate the molarity of the vinegar (molarity = mol/1Liter) You can use the concentration of acetic acid within vinegar to find the exact concentration (usually about 5%). It should be given. Percent volume should be fairly easy to determine - vol of acetic acid/vol of total fluid x 100.