Question

lim x->4 (-x^2+11x-28)/(x^2-4x)
So the limit is 3/4 but how do I end up getting that answer? The steps?

Answer 1

\[(-x^2+11x-28)/(x^2-4x)\]
Factor out an x in the denominator, factor the numerator.
\[(-(x-7)(x-4))/(x(x-4))\]
Divide out the (x-4)
\[-(x-7) / x\]
Now use direct substitution to find the limit as x approaches 4.