Question

guys anyone knw limits and continuity??

Answer 1

:-)

Answer 2

u knw??

Answer 3

maybe

Answer 4

meanss?

Answer 5

post question

Answer 6

k

Answer 7

find limit

Answer 8

(note dont use el hospital :))

Answer 9

\[\lim_{? \rightarrow 0} (x ^{3}\cot x)/(1-\cos x)=?\]

Answer 10

help

Answer 11

\[\lim_{x\rightarrow 0}\frac{x^3\cot{x}}{1-\cos{x}}=\lim_{x\rightarrow 0}\frac{x^3\cot{x}}{2\sin^2{(x/2)}}=\lim_{x\rightarrow 0}\frac{x^3\cos{x}}{2\sin^2{(x/2)}\sin{x}}=\]\[=\lim_{x\rightarrow 0}\frac{x^3}{2\sin^2{(x/2)}\sin{x}}=\lim_{x\rightarrow 0}\frac{4(x/2)^2x}{2\sin^2{(x/2)}\sin{x}}=\]\[=2\cdot\lim_{x\rightarrow 0}\left(\frac{x/2}{\sin{(x/2)}}\right)^2\cdot \lim_{x\rightarrow 0}\frac{x}{\sin{x}}=2\]

Answer 12

wow i hav some more do u hav board in twiddler?

Answer 13

nikvist??

Answer 14

..........plz reply?

Answer 15

no I haven't got

Answer 16

oh here its take long time to get answers done :) u see i hav tons of work to do?can u help a bit??

Answer 17

i am a great fan of u!!

Answer 18

send to my mail if you want?

Answer 19

wow thx a lot!!!!!!!!!!!!!THANK YOU THANK YOU THANK YOU!!!!!!!1

Answer 20

whats ur id?

Answer 21

nikvist@gmail.com

Answer 22

i sent a test mail u got it?

Answer 23

....

Answer 24

ok