Question

plissss help me help me

Let s,r,l are roots of x^3-8=0. Find integer n such that s^n=r^n=l^n !

Answer 1

why?

Answer 2

Sorry for the hasty answer.

Answer 3

oug ...
pliss help me

Answer 4

a^3 - 2^3 =0
Using the formula,
a^3 - b^3 = (a-b)(a^2 +ab + b^2)
We get,
(a-2)(a^2 + 2a + 4) = 0

One of the roots is 2 (say s)
But other two roots r and l are imaginary roots.
\[r= [ -2 +\sqrt{-12}]/2\]
\[l= [ -2 - \sqrt{-12}]/2\]

We want 'n' such that s^n = r^n = l^n
or
\[([ -2 +\sqrt{-12}]/2)^{n}\] = s^n = 2^n

But the imaginary number cannot be equal to 2.
So, there cannot be any value of 'n' which satisfies the above equality.

Answer 5

owh....thanks ^_^_^