Question

Solve the following equation by completing the square.
9x^2-12x=-1

Answer 1

\[x^2-\frac{4}{3}x=\frac{-1}{9}........x^2-\frac{4}{3}x+\frac{4}{9}=\frac{-1}{9}+\frac{4}{9}\]

Answer 2

\[(x-\frac{2}{3})^2=\frac{1}{3}\]\[x-\frac{2}{3}=+/-\sqrt{\frac{1}{3}}\]\[x=\frac{2}{3}+/-\sqrt{\frac{1}{3}}\]

Answer 3

That was close. It turned out to be \[\sqrt{3}/3 \] vs \[\sqrt{1}/3\]