a simulated water sample is determined to have an absorbance of .169 at 550.8 nm. determine the concentration of Fe(III) ions in the sample
What is the equation of the absorbance/concentration line?
Can't do much without that
ummm y= .0068x-.2562 i think i plotted it and got that equation
Ok, then it would be\[0.169=0.0068x-0.2562\]\[0.4252=0.0068x\]\[x=62.53\text{M}\] Is this something you did for an experiment? if so you might want to double check your plot, that is EXTRAORDINARILY concentrated for a Fe(III) sample. It is unlikely that any modern spectrometer would give you a absorbance of less than one for that concentration
well its just a pre-lab question. all of these are measured in PPM. y being absorbances at 550.8 and x being concentration in ppm
alrighty then, if its in ppm that's a bit more reasonable
haha alright tyvm
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