need help on the attachment

Question

anonymous · Answer

attachment

anonymous · Answer

you still here?

anonymous · Answer

guess not. idea is find 
$$f(0), f'(x), f'(0)$$ and then use point slope formula to find the equation for the line. i will write it out in any case

anonymous · Answer

$$f(x)=\frac{1}{\sqrt{5+x}}$$
$$f(0)=\frac{1}{\sqrt{5}}$$
$$f'(x)=-\frac{1}{2(x+5)^{\frac{3}{2}}}$$
$$f'(x)=-\frac{1}{5^{\frac{3}{2}}}=-\frac{1}{5\sqrt{5}}$$\]

anonymous · Answer

so by point-slope formula your line is 
$$y=-\frac{1}{5\sqrt{5}}x+\frac{1}{\sqrt{5}}$$

anonymous · Answer

ok a mistake i forget the 2 in the denominator of the derivative
it is 
$$y=-\frac{1}{10\sqrt{5}}x+\frac{1}{\sqrt{5}}$$

anonymous · Answer

looks like choice 3

anonymous · Answer

http://openstudy.com/users/ta123#/users/ta123/updates/4e94f0460b8b7d552aec4574

anonymous · Answer

hah i forgot the 2 as well!  lololol