I need to reverse simplify this: 5y²-3y+6. Anyone have a good system for reverse FOILing, it always takes me forever ~_~.
Reverse FOILing is called factorising, and these types with co-efficients infront of the variable squared are a pain in the butt, and ontop of that, this graph doesn't cut the x axis and it really difficult to factorise
Oh ok. Well i'm doing geometric sequences and trying to find the ratio so I can figure out the value of Y and according to the teachers notes this is the way to go about it and i'm comin up blank on the factorizing.
It can't be factorized, because the discriminant < 0
in my equation it is =0, I just didn't write it. So i did something wrong I guess. xD
Yes - that's right, the equation should be equal to zero. It must be equal to zero for it to be solved. I don't even know why your teacher would set anyone work to factorise this type of quadratic. The reason this can't be factorised is because b^2-4ac < 0. Therefore, in the quadratic formula, you cannot take the square root (as it is negative)
Well this is what I started out with: Find Y so that 4y+1, y+4, 10-y are consecutive terms. then i went (y+4)/(4y+1) = (10-y)/(y+4) then cross multiplied and ended up with what you see in the above posts.
The roots are imaginary... As you can see from the screenshot (drawn with Grapher)
Consecutive terms in a geometric sequence**
Is it solvable or is my teacher bonkers? lol
When you solve (y+4)/(4y+1) = (10-y)/(y+4) you do not get 5y²-3y+6. This could be your problem. Just a slight typo which has made an error in all our work. (y+4)/(4y+1) = (10-y)/(y+4) 5y^2-31y+6= 0 This would make more sense as this CAN BE factorised (as b^2-4ac > 0). Although I would use the quadratic formula as their is a coefficient infront of the y^2. I hope this has solved your dilemma. Are you aware of how to use the quadratic formula?
omg i typed 3y ~_~ sigh. I did get 31y but i apparently am unable to type a 1 lol sorry.
It's fine - do you need any further help factorising 5y^2-31y+6= 0?
And i'm not sure that I do. I'm taking a 30 level class after 10 years between when i took the pre-requisite and struggling to get my basics back.
What is the quadratic formula?
and yes i would seriously appreciate the help! haha
For a quadratic equation \[ax^2 + bx + c\] \[x = \frac{-b ± \sqrt{b^2 - 4ac}}{2a}\]
will i still get 2 values for x this way?
you can try calculatersoup.com
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