Question

Given the one-to-one function f(x)=(6x+1)/(x-2) , find f^-1(x) .

Answer 1

set
\[x=\frac{6y+1}{y-2}\] and solve for y

Answer 2

i did that so many times
i keep getting thesame answer but its wrong

Answer 3

\[x(y-2)=6y+1\]
\[xy-2x=6y+1\]
\[xy-6y=1+2x\]
\[(x-6)y=1+2x\]
\[y=\frac{1+2x}{x-6}\] so
\[f^{-1}(x)=\frac{1+2x}{x-6}\]
check my algebra because i make mistakes

Answer 4

okay one second thank you

Answer 5

its right! thanks so much. I tried it so many times