Question

What is the vertex form of y= 4x^2+20x+17? And how would you do it? (Please provide steps)

Answer 1

-5/2,-8

Answer 2

What would you get for the vertex form though? y= a(x+h)^2+k

Answer 3

parse out the x^2+x part

Answer 4

y= 4x^2 +20x +17

y= (4x^2 +20x) +17 ; now divide out the 4

y= 4(x^2 +5x) +17; and complete the square

Answer 5

y= 4(x^2 +5x +(5/2)^2) +17-4(5/2^2)

y= 4(x^2 +5x +(5/2)^2) +17-4(25/4)

y= 4(x^2 +5x +(5/2)^2) +17-25; and compact the square

y= 4(x+(5/2))^2 -8

Answer 6

Thanks!

Answer 7

yep