Sin (B-A) is equal to _____,when B= 270 degress and A is an acute angle.
i thought it is 90 degree but its not because of acute angle
This an odd question, but in short if A is acute then \[0 \leq A < 90\] and hence B-A is between 180 and 270 degrees. In which case sin(B-A) is a negative number.
IF the answer is negative the answer is -90 degree?
No, look at the direction of logical deduction in the statement: "Sin (B-A) is equal to _____,when B= 270 degress and A is an acute angle." That is "If B= 270 degress and A is an acute angle, then Sin (B-A) is equal to _____"
89 degree?
"If B= 270 degress and A is an acute angle, then Sin (B-A) is equal to A NEGATIVE NUMBER."
because of acute angle i confuse....acute angle is less than 90 degree but b-a is a negative number...
False. If A is between 0 and 90 and B = 270, then B - A is not negative Instead, B - A is between 180 and 270
Draw a diagram in the plane with a unit circle and see where B-A is. It is an angle that always lies in the 3rd quadrant.
aha 180 degree?
What question are you answering with "180 degrees"? I have already given you the answer to the question you posed at the beginning. What are you not understanding? I really think you should draw the diagram and see where the angle B-A is. It is in general an angle in the 3rd quadrant, but it is not one number. It is infinitely many angles, all of which lie in the third quadrant.
So what are examples of B - A on the diagram you just attached?
my prof not teach us that before im sorry i just do this for my project but i will i see a lot of degree in there between 90 degree and 270 degree
In the third quadrant only there is a range of 90 degrees: between 180 and 270 degrees. We are ONLY in the third quadrant because A is an acute angle. Hence A is between 0 and 90 degrees. Hence for B = 270 degrees, B - A is between 180 and 270 degrees.
i see a acute angle in the diagram 60 degree.. =210
For instance, yes.
what yes im correct?
210 is an example of an angle B - A when B = 270 and A is acute.
and sin(210) is a negative number.
In fact sin(270-A) is negative for all acute angles A.
i hate my professor y did he ask for a project like this with 13 question to go then pass tomorrrow then i feel like im home study i never learn from him
So what is the answer to the question: Sin (B-A) is equal to _____,when B= 270 degress and A is an acute angle
-0.5?
omg. You're not following me at all. Let's go through this again.
If A is acute it is ANY angle between 0 and 90 degrees. Agreed?
yes 2x
For example A = 30 degrees or A = 45 degrees or A = 60 degrees or A= 89.99 degrees or A = 1 degree or A = 25.666858458857564648696745 degrees
In every case, when A is between 0 and 90 degrees, 270 - A is an angle between 180 and 270 degrees
and that is the most general thing we can say about that angle.
When B = 270 degrees and A is acute, B-A can be ANY angle whatsoever between 180 and 270
That is, B - A is an arbitrary angle in the third quadrant.
So far, so good?
i confuse because the answer is negative u said 270-A is an angle between 180 and 270 degrees so far so good the answer is =-210........
Wait.
What do we know about the sin of an angle between 180 and 270 degrees?
What do we know about the sin of an angle in the third quadrant?
It is always negative.
yes i see in the picture there all negative
Hence sin(B-A) is negative when B = 270 and A is acute.
Therefore the answer to the question: "Sin (B-A) is equal to _____,when B= 270 degress and A is an acute angle" is Sin (B-A) is equal to A NEGATIVE NUMBER,when B= 270 degress and A is an acute angle
now i know my weakness i cant explain but i know the answer
sir i have 13 question to go i answer the others but no.13 -15 can u answer TT my head is aching i have 2 hours left to arrange my project TT
no, I have to go. Do yourself a favor and go back over this problem and make sure you understand it. If you do, I bet you the other questions will be easier.
ok thank u
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