Company decides to take random sample of 10 cell phones from production run of 2500 cell phones. Mean number of faulty cell phones is 1.6/day, what is probability of faulty cell phones produced tomorrow (one day has no bearing on the next). How to solve?

Question

anonymous · Answer

Correction: What is the probability that at least 1 faulty cell phone will be produced tomorrow*

anonymous · Answer

I'm trying to solve this, but everything I'm trying comes out with 400 and i don't think that would be correct.

anonymous · Answer

Similar example: mean = 4.8, prob at least 3 faulty cell phones is 0.8575

anonymous · Answer

Hopefully this will help. I never liked this subject. Haha http://oscience.info/math-formulas/probability-formulas/

anonymous · Answer

It's a bit more advanced

anonymous · Answer

Yes, what math are you taking? You're in college, right?

anonymous · Answer

Yes - Business Statistics

anonymous · Answer

I solved it:
1 - [p(x=0) + p(x=1) + p(x=2)]

Formula for each p is (e^(-lambda) x lambda)/x!