Question

Anyone that's good at FUNCTIONS online right now?

Answer 1

nope

Answer 2

:(

Answer 3

what's your problem? I'll give it a go!

Answer 4

cant

Answer 5

ill try

Answer 6

but i totaly fail at it

Answer 7

take u too long 2 type

Answer 8

f(x)=(radical 9 + x) - x - 6
f( (radical 2) +6

Answer 9

my mad geez

Answer 10

dammit, what does radical mean?

Answer 11

square root sign

Answer 12

oh

Answer 13

The sqr () smarty pants!

Answer 14

BTW parenthesis close after +6 so +6)

Answer 15

exactly, im not good at math, or functions

Answer 16

I know I have to plug the second part in for X but I keep getting the wrong answer...

Answer 17

u take 2 long 2 type

Answer 18

themathninja go away. you're not helping at all.

Answer 19

\[f(x)=\sqrt{9+x} - x-6\] and your \[f(\sqrt{2}+6)\], these are your two fuctions correct?

Answer 20

yes, except it's X + 9 not 9 + X but yeah...

Answer 21

In the second function you are defining what x is \[x= \sqrt{2}+6\] , so you must plug in \[\sqrt{2}+6\] wherever you see x so the function becomes \[f(\sqrt{2}+6) =\sqrt{9+\sqrt{2}+6} -\sqrt{2}+6-6\], clean that up a bit and you get \[f(\sqrt{2}+6) =\sqrt{\sqrt{2}+15} -\sqrt{2}\] .... are you sure you have the right function because this is not analytically solable?

Answer 22

i wrote it wrong at first. my bad...

Answer 23

:) It is okay. We all do that every once in a while.
Can you solve it now?

Answer 24

i was talking about the x+9, 9+x thing... but yes that is the problem i have on my hw

Answer 25

let me look something up okay

Answer 26

i put in what you have before and it said it was wrong... those radicals are messing me up

Answer 27

\[f(\sqrt{2})+6\]
or
\[f(\sqrt{2}+6)\]

Answer 28

the second

Answer 29

ok; and just one more clarification:

\[f(\sqrt{2}+6)\]or\[f(\sqrt{2+6})\]

Answer 30

the first

Answer 31

good

Answer 32

\[f(x)=\sqrt{9+x} - x-6\]

\[f(\sqrt{2}+6)=\sqrt{9+(\sqrt{2}+6)} - (\sqrt{2}+6)-6\]
\[=\sqrt{15+\sqrt{2}} -\sqrt{2}-6-6\]
\[=\sqrt{15+\sqrt{2}} -\sqrt{2}-12\]
that seems to be about the brunt of it, cant see if it simplifies more than that

Answer 33

I dropped a minus sign, he is right! I just reworked it, there is no way more to simply it.

Answer 34

That's correct but how does the positive 6 become a negative? Earlier they would have canceled out because they were opposites.

Answer 35

distribution law
\[- (\sqrt{2}+6)=- \sqrt{2}-6\]

Answer 36

There is a negative sign. infront of the -x which is -\sqrt[{2}-6

Answer 37

i see. thanks a lot! :D

Answer 38

the both of you

Answer 39

yep :)

Answer 40

youre welcome, i still drop a sign every day or so :)

Answer 41

Have 3 more functions to do. I'll see if I can do them again, if not, hopefully you guys can still help.

Answer 42

I posted another I need help with on the main board.