Use differentials to estimate the amount of paint needed to apply a 1/4 cms thick coat of paint to a sphere having diameter 4 cms.
Geometry? Find the volume of a sphere with diamete 4.5cm and subtract the volume of a sphere with diameter 4cm, and that will be the amount of paint, in cm cubed, you will need.
no, this is surface area
If you need to solve this using differentials (like you mentioned to me in chat), you will want to take a look at the surface area of the sphere. As if you painted the sphere over and over again until you had a 1/4 cm thick coating, you will want to find the total amount of surface areas added up in this process. The equation for surface area of a sphere is: \[A = 4\pi r^2\] So from this, you will want to first convert the diameters to radii; 4cm to 2cm, and 4.5cm (the diameter plus 0.25cm paint coating on each side) to 2.25cm. Then, you should solve this equation: \[\int\limits_{2}^{2.25} 4\pi r^2\] \[4\pi\int\limits\limits\limits_{2}^{2.25}r^2 = 4\pi \left[ (1/3)r^3 \right]_{2}^{2.25} = 4\pi \left[ (1/3)r^3 \right]_{2}^{2.25} = (4/3)\pi \left[ r^3 \right]_{2}^{2.25} = (4/3)\pi (2.25^3 - 2^3) \]\[\approx 14.2026\] You'll notice that solving that incredibly time-consuming integral essentially did the exact same thing as I mentioned before; by subtracting the without-paint-volume from the with-paint-volume.
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