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differentiate 3xe^x+4e^x
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might as well factor them and have only one product rule.
so y= e^(x) [ 3x+4]
dang it, i was wrong =[ Thank you
\[\frac{dy}{dx} = e^{x} ( \frac{d}{dx} (3x+4)) + (3x+4) \frac{d}{dx}(e^{x})\]
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so u just take the e^x out
because derivitive of e^x is e^x
\[= 3e^{x} + e^{x} [ (3x+4)] = 3xe^{x} +7e^{x}\]
I factored it first, then did product rule on the whole expression.
ahh
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calculus is ALL about putting it into relative workable chunks right elec? pretty easy once you get the hang of it.. all it takes is just seeing it. :D
true, true
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