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Is it possible to integrate ln x
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Yes, you must use integration by parts
\[\int{u}dv = uv - \int{v}du\]
choose ln(x) as your u, and dx as your dv
why are you complaining about doing tons of math when you already know calculus 2?
... my teacher teach differentiate 1/x = ln x... so integrate ln x=1/x...
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\[\int{\ln(x)}dx=x\ln(x)-\int\frac{xdx}{x}\]
he use the differentiation definition... f(x)=[f(delta x+x)-f(x)]/delta x
the integral of ln(x) is not 1/x, actually
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