I found this answer parts 1 and 2. please help parts 3-5.
2.5 Mg=2500 kg and 29 theta.
A car travels at a speed of 17 m/s around a
curve of radius 15 m.The acceleration of gravity is 9.8 m/s^2.
(Part 1 of 5)What is the net centripetal force needed to keep the car from skidding sideways?
Answer in units of N =48166.6 N
(part 2 of 5) Were there no friction between the car’s tires
and the road, what centripetal force could be
provided just by the banking of the road?
Answer in N=13580.57 N

Question

I found this answer parts 1 and 2. please help parts 3-5.
2.5 Mg=2500 kg and 29 theta.
A car travels at a speed of 17 m/s around a
curve of radius 15 m.The acceleration of gravity is 9.8 m/s^2.  
(Part 1 of 5)What is the net centripetal force needed to keep the car from skidding sideways?
Answer in units of N =48166.6 N			
 (part 2 of 5) Were there no friction between the car’s tires
and the road, what centripetal force could be
provided just by the banking of the road?
Answer in N=13580.57 N

anonymous · Answer

(part 3 of 5) .
Now suppose the friction force is suﬃcient to keep the car from skidding. Calculate the magnitude of the normal force exerted on the
car by the road’s surface. 
(part 4 of 5) 
Calculate the magnitude of the friction force.
Answer in units of N
 (part 5 of 5) Calculate the lowest possible value of the static friction coeﬃcient µs that would prevent the car from skidding.