Question

how do i evaluate dy when dy = sec^2(pi/3)(-.05) ?

Answer 1

I believe you are missing some info here...

Answer 2

what do you mean

Answer 3

y=sec^2(pi/3)(-.05x) perhaps?

Answer 4

not dy=...
then you would have nothing to do

Answer 5

Do you know how to evaluate \(\sin(\pi/3)\) and \(\cos(\pi/3)\) ? Remember that \(\sec(x) = \frac{1}{\cos(x)}\).

Answer 6

no i already plugged in values for x and dx where dx is -.05 and x is pi/3

Answer 7

The question is asking to *evaluate* -- so there is nothing that needs to be solved. If you know what cos(pi/3) is... take 1 over cos(pi/3) , square that, and multiply it by -1/2. :)

Answer 8

hmm..im confused haha

Answer 9

dy = Sec[Pi/3]^2 - 0.05 = 3.95