Can you completely factor 1(6x^2 + 29x - 5) ?

Question

anonymous · Answer

6x^2 + 29x - 5
or,6x^2 + (30-1)x - 5
or.6x^2 + 30x-x  - 5
or, 6x(x+5)-1(x+5)
or. (x+5)(6x-1)

turingtest · Answer

no GCF so let's try to factor
(6x^2 + 29x - 5)
(6x-1)(x+5)

anonymous · Answer

1(4x^2 + 13x - 12)

anonymous · Answer

=/

turingtest · Answer

I don't think it can be factored, but I'm not really positive, so I didn't post. let's see..
$$x=(-13 \pm \sqrt{13^2-4\times4\times-12})/8=(-13 \pm \sqrt{361})/8$$$$=(-13 \pm 19)/8=3/4,-4$$
so it should factor into 
(4x-3)(x+4)
which it does...

I did it the worst way possible :(

anonymous · Answer

Yeah I don't understand that, but thanks..

turingtest · Answer

Well I used the quadratic formula to see if it had rational answers, which because it did I was able to say 
x={-4,3/4}
which can only mean the factors are
(x+4)(4x-3)

turingtest · Answer

yeah, a lame way to do it...

anonymous · Answer

well I checked the numbers and it makes sense that way.. ><