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Mathematics 8 Online
OpenStudy (anonymous):

Exponent help

OpenStudy (saifoo.khan):

\[\Huge Exponent^{help}\]

OpenStudy (anonymous):

\[6^{7} \div 9^{7}\]

OpenStudy (anonymous):

i just don't get it

OpenStudy (saifoo.khan):

break it into parts.

OpenStudy (anonymous):

ok how

OpenStudy (mimi_x3):

128/ 2187 ?

OpenStudy (saifoo.khan):

\[\frac{2 \times 3 }{9^7}\]

OpenStudy (anonymous):

i have to make it into exponetial form

OpenStudy (saifoo.khan):

\[\frac{2}{3^{14-1}}\]

OpenStudy (anonymous):

ok and but what about the the 7 exponent

OpenStudy (saifoo.khan):

\[\frac{2}{3^{13}}\]

OpenStudy (saifoo.khan):

we multiplied it by 2.

OpenStudy (mimi_x3):

Can't you just use a calculator ?

OpenStudy (saifoo.khan):

Mini give her your calculator.

OpenStudy (anonymous):

i need to know how to do it manually

OpenStudy (mimi_x3):

Like she would want it. There's no point of knowing how to do it manually since you can use a calculator in exams

OpenStudy (saifoo.khan):

LOL.

OpenStudy (anonymous):

no luck for me, i can't use a calculator

OpenStudy (anonymous):

\[\frac{6^7}{9^7}=\frac{2^7*3^7}{(3^2)^7}\]\[=\frac{2^7*3^7}{3^{14}}\]good so far?

OpenStudy (anonymous):

good

OpenStudy (anonymous):

the numerator can be rewritten using\[(ab)^n=a^nb^n\] in the denominator, 9=3^2, then use the expo property\[\left( b^n \right)^m=b^{nm}\]and that is we we are in the problem so far

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

everything is good here and probably solved, correct?

OpenStudy (anonymous):

now if m > n, we have an expo property\[\frac{b^n}{b^m}=\frac{1}{b^{m-n}}\]so in our problem m=14 and n=7 (b=3 of course)\[\frac{2^7*3^7}{3^{14}}=\frac{2^7}{3^{14-7}}=\frac{2^7}{3^7}\]and this is the simplified exponential form; from this point the only thing to do is to simplify the 2^7=128 and the 3^7=2187

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