Exponent help
\[\Huge Exponent^{help}\]
\[6^{7} \div 9^{7}\]
i just don't get it
break it into parts.
ok how
128/ 2187 ?
\[\frac{2 \times 3 }{9^7}\]
i have to make it into exponetial form
\[\frac{2}{3^{14-1}}\]
ok and but what about the the 7 exponent
\[\frac{2}{3^{13}}\]
we multiplied it by 2.
Can't you just use a calculator ?
Mini give her your calculator.
i need to know how to do it manually
Like she would want it. There's no point of knowing how to do it manually since you can use a calculator in exams
LOL.
no luck for me, i can't use a calculator
\[\frac{6^7}{9^7}=\frac{2^7*3^7}{(3^2)^7}\]\[=\frac{2^7*3^7}{3^{14}}\]good so far?
good
the numerator can be rewritten using\[(ab)^n=a^nb^n\] in the denominator, 9=3^2, then use the expo property\[\left( b^n \right)^m=b^{nm}\]and that is we we are in the problem so far
ok
everything is good here and probably solved, correct?
now if m > n, we have an expo property\[\frac{b^n}{b^m}=\frac{1}{b^{m-n}}\]so in our problem m=14 and n=7 (b=3 of course)\[\frac{2^7*3^7}{3^{14}}=\frac{2^7}{3^{14-7}}=\frac{2^7}{3^7}\]and this is the simplified exponential form; from this point the only thing to do is to simplify the 2^7=128 and the 3^7=2187
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