Question

Differentiate f(x)=yln(6+e^y)

Answer 1

f(x)=yln(6+e^y), not x? but y?

Answer 2

yea... this is one of my issues

Answer 3

It's a trick. With no other information, then y here is just a constant and hence f(x) it itself a constant function. Hence df/dx = 0.

Answer 4

not correct. just input it into webassign.

Answer 5

In which case either it's an error and you should consider all the ys to be xs. Or, you should consider y as a function of x itself and use the chain rule/implicit differentiation. I'd try the first of those two first.

Answer 6

my bad its f(y)=....

Answer 7

there you are then.

Answer 8

so what do i need to do it it? I've only got like one more try. and I dont come here until its almost too late lol. try to swing it on my own

Answer 9

Chain rule and product rule. You need to try and sweat this out; it's how you learn.

Answer 10

i'm working on it lmao! do you go to college still? whats your major?

Answer 11

For instance let u = y, v = ln(6+e^y)

Then df/dy = du/dy . v + u . dv/dy

Now you need to figure out how to differentiate v, and that's the chain rule.

Answer 12

I'm a mathematician slumming it.

Answer 13

i'm majoring in math right now... want to do applied and industrial math. Hows the pay? and how hard is the job market?

Answer 14

Impossible questions to answer in general, but in short good mathematicians are in short supply; and good ones can do this problem in their heads.

go back to this question you asked:
http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4e9a31410b8ba77642a9c5ee

Make sure you understand every step. If you do, you should have few problems here.

Answer 15

well i got my ged in 1997 and started college in 2009 after a few times of jail and stupid stuff. so in my head aint quite there yet. but it comes decently easy once shown in detail once. Thanks for your time!

Answer 16

so i got 1+ 1/(6+e^y)*e^y and that still aint right. guess i'll just bring it to my professor

Answer 17

is suppose to say f(y)=yln(6+e^y) ?

Answer 18

\[f'(y)=(y)'\ln(6+e^y) +y[\ln(6+e^y)]'\]

Answer 19

I did it !!!!!!!!!!!!!!!!!! thanks myininaya and JamesJ

Answer 20

np