Question

Suppose f '(2) = 3 and g '(2) = 8
Find h'(2) where h(x) = 5f(x) + 3g(x) +1
h'(2) =

Answer 1

h'(x) = 5f'(x) +3g'(x) +1
=> h'(2) = 5(3) +3(8) +1
=15+24+1
= 40

Answer 2

is this ur ans!!!

Answer 3

the answer to the problem said that it was 39:PP its like an online hw assignment

Answer 4

i dont know how its 39 though

Answer 5

ohhhhhhhhhhh i'am sorry i made a mistake!!!

Answer 6

h'(x) = 5f'(x) +3g'(x) +1
=> h'(2) = 5(3) +3(8)
=15+24
= 39
(if we differentiate 1 we get 0)

Answer 7

ohhh i see haha
thank you:)

Answer 8

h[x] = 5 f[x] + 3 g[x] + 1
h'[2]=5 f ' [2]+3 g'[2]
h'[2]=5*3 + 3*8
h'[2]=15 + 24
h'[2]=39

Answer 9

myinmi, hello, i think i see why the discrepancy in my problem

Answer 10

in the problem you have to take the square root of tan^2 theta, but we know that the square root of x^2 is |x|, and for the theta in the problem we have a negative answer