For what interval is the function
f(x) = (20 + \sqrt{x}) / (\sqrt{20 + x})
continuous?
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OpenStudy (jamesj):
Well, first was is the domain of this function?
OpenStudy (jamesj):
what is
OpenStudy (anonymous):
The domain of this function is [-20, infinity)
OpenStudy (jamesj):
No, it's not.
OpenStudy (anonymous):
No sorry
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OpenStudy (anonymous):
The domain it is: (-20,0]
OpenStudy (jamesj):
Noo....
OpenStudy (anonymous):
What?#$
OpenStudy (anonymous):
Then what would it be? This is why I think it is that:
The domain of the numerator is [0, infinty)
The domain of the denominator is (-20, infinity)
The intersection of these two domains is (-20,0]
OpenStudy (jamesj):
The intersection of the two domains is
[0, infinity)
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OpenStudy (anonymous):
Why?
OpenStudy (jamesj):
Is -1 in both domains? Is -10 in both domains?
OpenStudy (jamesj):
But is 1 in both domains?
OpenStudy (anonymous):
for x greater than zero
OpenStudy (anonymous):
Oh I see. It makes sense because the square root of x only accepts positive real numbers.
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OpenStudy (anonymous):
yes
OpenStudy (jamesj):
And zero, yes.
OpenStudy (jamesj):
Now, where is it continuous?
OpenStudy (anonymous):
for every x greater than zero it will be continuous not at any specific point
OpenStudy (anonymous):
Yes I understand, please help me out with my other question.
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OpenStudy (turingtest):
@sumbul What to you mean "not at any specific point"?
OpenStudy (anonymous):
in full interval
OpenStudy (turingtest):
the answer is [0,infty)
so every x greater-than or equal-to zero