Question

please help me.. i'm answering algebraic fractions..

Answer 1

you have to post your question first =p

Answer 2

\[[(x ^{2}-y ^{2})/x ^{3}-y ^{3}] \div [(x+y)/x]\]

Answer 3

the first term equal 1

1/(x+y)/x = 1 * x/(x+y) = x/(x+y)

Answer 4

how did you get it?

Answer 5

x2 -y2
------ =1
x2 -y2

Answer 6

or the denominator is x3-y3 ???

Answer 7

yes

Answer 8

so than you can write this like (x-y)(x2+xy+y2)

Answer 9

and will get (x-y)(x+y)/(x-y)(x2+xy+y2)

Answer 10

what will be equal (x+y)/(x2+xy+y2)
and this you need divide by (x+y)/x
yes ???

Answer 11

so than because you know that when we need divide two fractions this is equal the first fraction multiply by second inversed

Answer 12

yes ?

Answer 13

hence we get
(x+y)/(x2+xy+y2) * x/(x+y)

Answer 14

right ???

Answer 15

but you can simplify again by (x+y) and will get like result x/(x2+xy+y2)

Answer 16

hope so much that you have understood it all

Answer 17

yes :::

Answer 18

???

Answer 19

so than please push the good answer button

Answer 20

thank you

Answer 21

ii can't really understand it :(

Answer 22

why ???

Answer 23

what you cant understanding ?

Answer 24

this is very easy

Answer 25

is the answer (x+y)/x?

Answer 26

not is x/x2+xy+y2

Answer 27

(x+y) is simplified

Answer 28

can you please show me how you solved it? i'm really sorry i'm very bad at math..