Question

Pleaseee help me solve by completing the square

Answer 1

2x^2 + 4x + 5 = 0

Answer 2

(1) subtract 5 on both sides
(2) factor out 2 on the left hand side
(3) divide both sides by 2
(4) add (2/2)^2 on both sides to complete the square on the left hand side
(5) so you can now write (x+1)^2=-5/2+1

Answer 3

i see you reposted the problem
you have a negative on the right hand side
if you take the square root of that you get imaginary answer so where is i?

Answer 4

Oh oh I meant
x = -1 +- i(√3/2)

but that answer still doesn't match the answers sheet

Answer 5

is that square root over 3/2
or just over 3?

Answer 6

It's supposed to be (-2 +- i√6) 2

Answer 7

Square root I put over both

Answer 8

(-2 +- i√6) /2 **

Answer 9

so we have
\[x=-1 \pm i \sqrt{\frac{3}{2}}=-1 \pm i \frac{\sqrt{3}}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}}\]
\[=-1 \pm i \frac{\sqrt{6}}{2}\]
now what do you have if you combine the fractions?

Answer 10

:o

Answer 11

THANK YOU!!!!