Question

Factor the polyomial completely using any method r^5+r^3-r^2-1
Medal given for answer

Answer 1

\[r^5+r^3-r^2+1\]factor out the GCF from the first two terms, and the -1 from the second two\[=r^3(r^2-1)-(r^2-1)\]factor out the binomial\[=(r^2-1)(r^3-1)\]

Answer 2

thanks medal given :)

Answer 3

this problem is not yet completely factored; look at you original problem is the last term supposed to be POSITVE?

Answer 4

no its right

Answer 5

r^3(r^2 + 1) - (r^2 + 1)
(r^3 - 1)(r^2 + 1)

Answer 6

furthermore,
(-1+r) (1+r+r^2)(r^2 + 1)

Answer 7

then my last line is incorrect it should be
\[=r^3(r^2+1)-(r^2+1)\]\[=(r^2+1)(r^3-1)\]the second binomial is a difference of cubes\[=(r^2+1)(r-1)(r^2+r+1)\]and this is the factored form.