Question

3e ^x+1 - 2=0 solve for x

Answer 1

start with
\[3e^{x+1}=2\] then
\[e^{x+1}=\frac{2}{3}\] write in equivalent logarithmic for to get
\[x+1=\ln(\frac{2}{3})\] then subtract 1 to get
\[x=\ln(\frac{2}{3})-1\]

Answer 2

thanks so much

Answer 3

yw