Question

How do you solve (a+4/3a)+(2a-1/5a^2)?
Please explain.

Answer 1

is it 4/(3a) in the first part?
i.e. is a in the denominator?

Answer 2

No, its a+4 in the denominator.

Answer 3

I mean numerator sorry

Answer 4

3a is the denominator

Answer 5

I get it but the equation thing is broken, sorry just a sec...

Answer 6

(a+4)/(3a)+(2a-1)/(5a^2)
right?

Answer 7

yes

Answer 8

\[{(a+4)\over(3a)}+{(2a-1)\over(5a^2)}\]there we go...

Answer 9

exactly

Answer 10

get a common denominator, which is 15a^2:
wait, do you need to solve or simplify?

Answer 11

is it =0?

Answer 12

No, its not equal to anything, so I guess I'm just simplifying.

Answer 13

Ok, I got the common denominator.

Answer 14

ok,
get a common denominator, which is 15a^2:
\[{5a(a+4)\over(5a)(3a)}+{3(2a-1)\over3(5a^2)}={5a^2+20a+6a-3\over15a^2}\] continuing...

Answer 15

\[={5a^2+26a-3\over15a^2}\]well that doesn't factor any further so... It seems we're done.

Answer 16

yes that is the answer, Wolfram agrees.

Answer 17

Thanks I get it now,