Question

-3|2x+1|>9

Answer 1

-3|2x + 1| > 9
|2x + 1| < -3

not possible, since | 2x + 1| >= 0 and can never be negative.

Ans. No solution

Answer 2

Thank you.

Answer 3

Can it be graphed on a number line though?

Answer 4

nvm i guess not bye

Answer 5

2x+1<-3 & 2x+1<3
-1 -1 -1 -1
2x< -4 2x< 2
/2 /2 /2 /2
x< -2 & x<1

Answer 6

Use the one you need

Answer 7

there is no solution though

Answer 8

@twignamanda

|2x+1| < -3

means

3 < 2x + 1 < -3
2 < 2x < -4
1 < x < -2

So x < -2 AND x > 1 at once, which is impossible

Answer 9

Another way to see this is to imagine two functions

y1 = 9
y2 = -3|2x + 1|

can -3 ever be greater than 9 as when x = 1 ?

Since there is at least one point where y2 is not greater than y1, then for all x, y2 is not greater than 9

y2 > y1 means for all x (in the domain) this is true, where obviously in the case above, we found one case where this is not.

Answer 10

http://www.wolframalpha.com/input/?i=-3 |2x%2B1|%3E9