Question

Explain this to me please.

Answer 1

thats easy

Answer 2

ok can you explain it

Answer 3

Yeah, these used to hang me up until I understood what q(x) and p(x) really mean.

Answer 4

what do these represent? lol

Answer 5

you plug in the values of x to the innermost function then plug the result of that into the outside function so for like p(q(x)) at x = 1 you would do q(1) which is 5 then do p(5) which is 2

Answer 6

anything inside the parentheses represent x values. The x values are the first line of numbers in the boxes given above. All you do is, for example if you're given say, q(4), you find the appropriate x = 4 then find the corresponding column of q(x) values. Find where q(x) and x = 4 intersects. The value in the box will be what q(4) equals.

For something like q(p(4)), always remember that the value inside the parentheses represents an x value. So first, you'll have to begin with the innermost set of parentheses. Find p(4). Then replace p(4) with its corresponding value. then evaluate q(p(4)).

Answer 7

Techno, I hope you didn't give up

Answer 8

5, 2, 0, 4, 3, 1...but i don't understand how some of them came up to that answer.
for instance 2=0, how is that?

Answer 9

Wait, let me post something you might understand:

so for x = 1, p(q(x)) becomes p(q(1)). We begin with the innermost function. q(1) means find find the row of q(x) and the column of x = 1. The box where both intersects is the value for q(1). q(1) = 5

So now, since q(1) = 5, we replace p(q(1)) with p(5). Now x = 5 and p(x) is the function. So we find the row p(x) and the column x = 5. We intersect the two to get p(5) = 4

Unfortunately, if you made it this far, it's where it can get a little confusing.

The reason why we're doing all of this is because we needed to find r(x) where x = 1 because r(x) = p(q(x)) and r(1) = p(q(1)).

This may or may not make sense, but we found that r(1) = 4